on number 4 part c, you said that C=2pir=40 cm. are we supposed to solve for r and plug that into the equation for area of a circle (pir^2)?
when i did that, i ended up with the square having the biggest torque, then the circle, then the triangle, and i thought you said the circle should have the biggest torque.
i can't upload the document.
ReplyDeleteme either..
ReplyDeletehavin problem openin it.....
ReplyDeleteOk, that was my fault ... wrong file uploaded.
ReplyDeleteIt should work now!
on number 4 part c, you said that C=2pir=40 cm. are we supposed to solve for r and plug that into the equation for area of a circle (pir^2)?
ReplyDeletewhen i did that, i ended up with the square having the biggest torque, then the circle, then the triangle, and i thought you said the circle should have the biggest torque.
You are right to set C=2pir and solve for r. Then the area is pi*r*r ... which should still give the largest area (and thus torque) for the circle.
ReplyDeleteSquare: each side is 40/4 or 10cm.
Not sure why it is coming out that the square has the biggest torque, but I would double check your areas.