Tuesday, July 27, 2010

Exam II this Thursday

Exam II is this Thursday. Same as last time, it will be held during the lab period, and we will have a lecture that day as well. The format will be nominally identical: you can skip 2 of the problems, you can bring a formula sheet, there won't be any multiple choice. I'll provide the basic formulas, also like last time. Basically, same thing, different material.

For the material, here's what it looks like:

Covered on exam II
  • Book Ch. 18 (notes Ch. 5): end of dc circuits (combining resistors, multiple loops)
  • Book Ch. 19 (notes Ch. 6) Magnetism (nothing on Ampere's law or the relativity stuff)
  • Book Ch. 20 (notes Ch. 7) Induction
  • Book Ch. 21 (notes Ch. 8) ac circuits (filters and audio circuits, basically)
  • Book Ch. 21 (notes Ch. 8) EM waves (very little there, honestly.)
  • Book Ch. 22 (notes Ch. 9) reflection / refraction (mirrors, refraction; no lenses)
The questions will be a bit heavier on circuits, magnetism, and induction (maybe 2 questions each) with not so much on EM waves or the start of optics (maybe 1 question each). More details to follow as the week proceeds ...

I will not make this exam purposely more difficult than the last one. However, most people find this material harder than the material from the first exam, in my experience. If you study the old homework & exam questions, you will probably be fine (presuming you've kept up with reading the notes or textbook).
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6 comments:

  1. AnonymousJuly 27, 2010 at 10:19 PM

    a few of the old test II's from previous classes are missing the answers, is there any way you could post the answers to them?

    ReplyDelete
  2. pleclairJuly 27, 2010 at 10:22 PM

    If you tell me which ones, I can at least post the answers, if not full solutions.

    ReplyDelete
  3. AnonymousJuly 28, 2010 at 9:41 AM

    summer 2008 exam II.. thank you!

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  4. AnonymousJuly 28, 2010 at 4:03 PM

    On Quiz 6 from 2007, #4, I understand the explanation about the induced current and force in position A, but could you explain why the situation is reversed in position B? Thanks.

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  5. pleclairJuly 28, 2010 at 5:30 PM

    I'll try to post the answers as soon as I can, but it might be 9ish tonight ...

    For Q6/2007, you want to think about what the change in flux is. At point A, the flux is increasing, so the currents will circulate to make their own field which will try to cancel out part of the B field being applied.

    At point B, the flux is *decreasing* as the pendulum swings through, so the circulating currents will want to add to the existing B field to stop the decrease.

    Does that make any more sense?

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  6. pleclairJuly 28, 2010 at 6:07 PM

    I actually had a solution for exam II, summer 2008 and never posted it.

    Here you go.

    ReplyDelete