are out for your studying pleasure.
UPDATE: I corrected a dumb mistake in 3a - I forgot to multiply by 4 when I collected all of the q5 terms, so the answer should be 4-15*sqrt(2) times the energy of a single pair, or about -17.21 as pointed out in the comments. The link above has the corrected version.
UPDATE: Small mistake in 1b as well - the initial formula for acceleration is OK, but the final expression where I've plugged in the result for d was incorrect, as was the numerical answer. Fixed now.
UPDATE: I corrected a dumb mistake in 3a - I forgot to multiply by 4 when I collected all of the q5 terms, so the answer should be 4-15*sqrt(2) times the energy of a single pair, or about -17.21 as pointed out in the comments. The link above has the corrected version.
UPDATE: Small mistake in 1b as well - the initial formula for acceleration is OK, but the final expression where I've plugged in the result for d was incorrect, as was the numerical answer. Fixed now.
THANKS!!
ReplyDeleteCan you explain the answer for 3a. When you worked it out in class you got different numbers for the charges that involved the -4q.
ReplyDeleteIn 3a isn't there supposed to be 4 of the (Keq^2)/(a)(sqrt2/2) so would the answer be -17.21 instead of -5.9?
ReplyDeleteAh, my bad. I dropped a factor 4, the last one should be -17.21. Will repost the file with corrections. Should not do these things so late at night ...
ReplyDeleteI don't understand why #1 part b is worked out the way that it is. I can't get get the right number even working through it exactly. Also, why is acceleration in newtons and not m/s^2? Could you please explain?
ReplyDeleteYou're right - see update to top level post. The initial expression is fine, but I made a typo in plugging in the result for d. This made the numerical answer incorrect as well. The units should be m/s^2 as you point out, also fixed.
ReplyDelete